Pyetja #530 - Kimi

Question

Barazimi jonik për reaksionin e mëposhtëm: $$ \text{AgNO}_3{}_{(aq)} + \text{HCl}_{(aq)} \rightarrow \text{AgCl}_{(s)} + \text{HNO}_3{}_{(aq)} $$ është: A) $\text{Ag}^{+}_{(aq)} + \text{Cl}^{-}_{(aq)} \rightarrow \text{AgCl}_{(s)}$ B) $\text{Ag}^{+}_{(aq)} + \text{NO}_3^{-}{}_{(aq)} \rightarrow \text{Cl}^{-}_{(aq)} + \text{NO}_3^{-}{}_{(aq)}$ C) $\text{Cl}^{-}_{(aq)} + \text{H}^{+}_{(aq)} \rightarrow \text{Cl}^{-}_{(aq)} + \text{H}^{+}_{(aq)}$ D) $\text{NO}_3^{-}{}_{(aq)} + \text{H}^{+}_{(aq)} \rightarrow \text{H}^{+}_{(aq)} + \text{NO}_3^{-}{}_{(aq)}$

Amarildo Koçiaj · Accepted Answer

Pyetja

Barazimi jonik për reaksionin e mëposhtëm:

\[ \text{AgNO}_3{}_{(aq)} + \text{HCl}_{(aq)} \rightarrow \text{AgCl}_{(s)} + \text{HNO}_3{}_{(aq)} \]

është:

A) $\text{Ag}^{+}_{(aq)} + \text{Cl}^{-}_{(aq)} \rightarrow \text{AgCl}_{(s)}$

B) $\text{Ag}^{+}_{(aq)} + \text{NO}_3^{-}{}_{(aq)} \rightarrow \text{Cl}^{-}_{(aq)} + \text{NO}_3^{-}{}_{(aq)}$

C) $\text{Cl}^{-}_{(aq)} + \text{H}^{+}_{(aq)} \rightarrow \text{Cl}^{-}_{(aq)} + \text{H}^{+}_{(aq)}$

D) $\text{NO}_3^{-}{}_{(aq)} + \text{H}^{+}_{(aq)} \rightarrow \text{H}^{+}_{(aq)} + \text{NO}_3^{-}{}_{(aq)}$

Zgjidhja hap pas hapi

Reaksioni i dhënë është reaksion precipitimi, sepse formohet klorur argjendi $\text{AgCl}_{(s)}$, i cili është i patretshëm në ujë.

Barazimi molekular është:

\[ \text{AgNO}_3{}_{(aq)} + \text{HCl}_{(aq)} \rightarrow \text{AgCl}_{(s)} + \text{HNO}_3{}_{(aq)} \]

Shpërbashkimi i elektroliteve të tretshme

Nitrat argjendi $\text{AgNO}_3$ është i tretshëm në…

Informatest