Pyetja #719 - Kimi

Question

Funksionimi i një elementi galvanik bazohet në gjysmëreaksionet: $$ MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O_{(l)} \quad E^0 = +1.52 \text{ V}$$ $$Cl_2(g) + 2e^- \rightarrow 2Cl^-_{(aq)} \quad E^0 = +1.36 \text{ V} $$ Reaksioni i përgjithshëm jonik dhe potenciali standard i elementit (f.e.m), janë: A) $ MnO_4^- + 8H^+ + Cl_2(g) \rightarrow Mn^{2+} + 4H_2O_{(l)} + 2Cl^- \quad E^0 = +2.88 \text{ V} $ B) $ Mn^{2+} + 4H_2O_{(l)} + 2Cl^- \rightarrow MnO_4^- + 8H^+ + Cl_2(g) \quad E^0 = +0.12 \text{ V} $ C) $ 2MnO_4^- + 16H^+ + 10Cl^- \rightarrow 2Mn^{2+} + 8H_2O_{(l)} + 5Cl_2(g) \quad E^0 = +0.16 \text{ V} $ D) $ Mn^{2+} + 4H_2O_{(l)} + Cl_2(g) \rightarrow MnO_4^- + 8H^+ + 2Cl^- \quad E^0 = -2.88 \text{ V} $

Amarildo Koçiaj · Accepted Answer

Pyetja

Funksionimi i një elementi galvanik bazohet në gjysmëreaksionet:

\[ \text{MnO}_4^- + 8\text{H}^+ + 5e^- \rightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O}_{(l)} \qquad E^0 = +1.52\ \text{V} \]

\[ \text{Cl}_2{}_{(g)} + 2e^- \rightarrow 2\text{Cl}^-_{(aq)} \qquad E^0 = +1.36\ \text{V} \]

Reaksioni i përgjithshëm jonik dhe potenciali standard i elementit, f.e.m., janë:

A) $\text{MnO}_4^- + 8\text{H}^+ + \text{Cl}_2{}_{(g)} \rightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O}_{(l)} + 2\text{Cl}^- \quad E^0 = +2.88\ \text{V}$

B) $\text{Mn}^{2+} + 4\text{H}_2\text{O}_{(l)} + 2\text{Cl}^- \rightarrow \text{MnO}_4^- + 8\text{H}^+ + \text{Cl}_2{}_{(g)} \quad E^0 = +0.12\ \text{V}$

C) $\text{2MnO}_4^- + 16\text{H}^+ + 10\text{Cl}^- \rightarrow 2\text{Mn}^{2+} + 8\text{H}_2\text{O}_{(l)} + 5\text{Cl}_2{}_{(g)} \quad E^0 = +0.16\ \text{V}$

D) $\text{Mn}^{2+} + 4\text{H}_2\text{O}_{(l)} + \text{Cl}_2{}_{(g)} \rightarrow \text{MnO}_4^- + 8\text{H}^+ + 2\text{Cl}^- \quad E^0 = -2.88\ \text{V}$

Përcaktimi i katodës dhe anodës

Të dy gjysmëreaksionet janë dhënë si reduktime.…

Informatest