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Për shndërrimin e mëposhtëm të benzenit:

\[ \text{C}_6\text{H}_6 + X \xrightarrow{\text{AlCl}_3} Y \xrightarrow{\text{Cl}_2/\text{dritë}} Z \xrightarrow{\text{KOH}/\text{etanol}} W \xrightarrow{\text{H}_2\text{O}/\text{H}_2\text{SO}_4} \text{C}_6\text{H}_5\text{C}(\text{OH})(\text{CH}_3)_2 \]

formulat e përbërjeve sipas radhës \(X\), \(Y\), \(Z\), \(W\) janë:

A) \(X: \text{CH}_3\text{CH}_2\text{CH}_2\text{Cl}\);
\(Y: \text{C}_6\text{H}_5\text{CH}(\text{CH}_3)_2\);
\(Z: \text{C}_6\text{H}_5\text{CCl}(\text{CH}_3)_2\);
\(W: \text{C}_6\text{H}_5\text{C}(\text{CH}_3)\text{CH}_2\)

B) \(X: \text{CH}_3\text{CHClCH}_3\);
\(Y: \text{C}_6\text{H}_5\text{CH}(\text{CH}_3)_2\);
\(Z: \text{C}_6\text{H}_5\text{CCl}(\text{CH}_3)_2\);
\(W: \text{C}_6\text{H}_5\text{C}(\text{CH}_3)\text{CH}_2\)

C) \(X: \text{CH}_3\text{CHClCH}_3\);
\(Y: \text{C}_6\text{H}_5\text{CH}(\text{CH}_3)_2\);
\(Z: \text{C}_6\text{H}_4\text{ClCH}(\text{CH}_3)_2\);
\(W: \text{C}_6\text{H}_5\text{C}(\text{CH}_3)\text{CH}_2\)

D) \(X: \text{CH}_3\text{CH}_2\text{CH}_2\text{Cl}\);
\(Y: \text{C}_6\text{H}_5\text{CH}(\text{CH}_3)_2\);
\(Z: \text{C}_6\text{H}_4\text{ClCH}(\text{CH}_3)_2\);
\(W: \text{C}_6\text{H}_5\text{C}(\text{CH}_3)\text{CH}_2\)

Identifikimi i përbërjes \(X\)

Në hapin e parë ndodh alkilimi Friedel-Crafts i benzenit në prani të \( \text{AlCl}_3 \).

Produkti që duhet të vazhdojë reaksionet e mëtejshme është izopropilbenzeni:

\[ Y = \text{C}_6\text{H}_5\text{CH}(\text{CH}_3)_2 \]

Për të vendosur grupin izopropil në unazën benzenike, halogjenalkani më i përshtatshëm…